### Writing Expressions

November30

**Write an expression for the sequence of operations:**

**Add 3 to x, subtract the result from 1, then double what you have.****Add 3 to x, double what you have, then subtract 1 from the result.**

**HINT: Parenthesis force you to do operations before other operations!**

2[1-(x+3)]

[1-(x+3)]2

1. 2[1-(x+3)] 2. [2(x+3)]-1

1. 2[1-[x+3]

2. [2*[x+3]-1]

———————————————————————————————–

2[1-(x+3)] 1-[2(3+x)]

1-(3+x)*2=blank

1(3+x)*2

* (3+x-1)2

* 2(3+x) -1

1+x

5+x

so the problem says add 3 to x double what you have then subtract 1 from the result. so

3+x

double 3 and you get 6

plug 6 in for x

6-1=5

so 3+5=8

eight is the answer ðŸ™‚

1.(3+x)-1 *2

2. 3+x(2) -1

* = multiply

what i did was i went word by word so this is how the first equation came out 3+x=-1*2

this is how the second equation came out (3+x)the power of 2-1 that is how my equations turned out

2[1-(X-3)]

1[2(x+3)]

Is 1-(x+3) the same as (x+3)-1?

2[1-(x-3)]

1-[2(x+3)]

and thats the equations

1.2[1-(x+3)]

2.[2x(x+3)]-1

This is the real answer.

(3+x)-1*2

(3+x)*2-1

If you want an operation to come before another you can use () to force it to come first!

3+x=4,4-1=3â€¢2=6 3+x=4Ã—2=8,8-1=7

Can you write these as an expression without an equal sign?

The first operations would be (3+x-1)(2) because the order of operations makes you do parenthesis first then multiplication and last the subtraction.

The second sequence would be written (3+x)(2)-1 because this order tells you to first subtract then multiply and last subtract.

To check my work i used P.E.M/D.A/S and plugged in 5 for x on both equations and got 14 for the first and 15 for the second which shos that the answer changes if you change the order.

my first one is (3+x-1)x2

my second one is (3+x*2)-1

1) (1-(3+x)).2

2) ((3+x)(2))-1

1. 1-(x+3)

2. (x+3)2-1

1. 2[1-(x+3)]

2. [2*(x+3)]-1

Is 1-(x+3) the same as (x++3)-1?

1-(x+3)

2*(x+3)-1

when you add 3 then subtract 1 then doubel it you get 4 as your answer what im trying to say is if you add 3 to x then subtract 1 then doubel it you will get 4 as your answer

Can you write this as an expression?

(3+x)- 1 x 2

(3+x) x 2 – 1

If you want a certain operation to come before another operation you need to put () around it to tell it to come first!

1. (3 + x) – 1 x 2 =

2. (3 + x) 2 – 1 =

If you want a certain operation to come before another operation you need to put () around it to tell it to come first!

The first expression is (3+x-1)â€¢2.

The second expression is (3+x)â€¢2-1

1) (3+x)-1×2

2) (3+x)x2-1

If you want to force an operation to come first you can put () around it!

[1-(3+x)] x2

3+x-1

1-3=-2

1. The expression would be 3+x-1(2) because you have to add 3+x and then subtract 1 and lastly multiply it by 2 and when there is parenthesis it can also mean multiplication.

2. The expression would be 3+x(2)-1 because now you have to add 3+x just like in the other expression but multiply the answer you get by 2 and whatever that equals you have to subtract it from 1.

what my result was that I had gotten 6.

add 3 to x

doulble 3 would be 6

then you subtract 1 from 6

THEN YOUR AWNSER IS 5

(x+3)-1=?

2 (3+x) -1

3+x=4

(3+x-1)*2

( 3+x) *2)-1

reason being is that you want to add first so you want to add parentheses in order to do it first. ðŸ˜›

the expression for this sequence and operations is (3x-1)then(3xand3x-1) that is what I think ok.:)

1-(3+x)2

(3+x)2-1

1. x+3-1=2. 2 doubled is 4

2. x+3=x+6-1=5

1. (3+x -1)2

2. (3+x)(2) -1

The first one is (3+x -1)2

And the second one is…

(3+x)(2) -1

Oh no! Who does this belong to?

the first equation would be 1-(3+x) x 2

The second equation would be 2(3+x)-1

If you want an operation to come before another operation, you need to use () to tell it to go first!

The first one is (3+x -1)2

And

The second one is (3+x)(2)1

If you have a number next to () without an operation symbol it means you are multiplying. Did you mean to multiply by 2 and 1?

(x+3-1)x2

(x+3-1)x2 is the expression

You should have TWO expressions here!

x=2

[(3+2)-1] x 2

5(2)

10=10

x=4

[(3+4)x 2]- 1

14-1

13

You should be writing an expression with variables for this problem.

1. 3x-(1×2)

2.3x(x2-1)

Make sure you read the question VERY CAREFULLY and then double check your work against it!

2(x+3-1)

2(3+x)-1

5

You should have two expressions written there. What is 5?

2(1-(3+x))

You should have TWO expressions!

1)( 3+x)-1)â€¢2

2)(3+x)â€¢2)-1

The first one would be 2(-1(3+x) because first we would have multiplication so it would be the 2 then we would put the -1 next to it with parenthesis then in parenthesis you would also put adding the 3 and x. For the second one it would be 2(x+30(-1). I but the two first because multiplication comes first then I put the 3 + x because subtracting is at the end.

If you have an number that is in front of () without an operation sign between them, it means multiply. Did you mean to multiply by -1?

sorry made a little error, here is the correct one

expression one. (x+3-1)2

expression two. (3+x)2-1

2(1-(3+x))

2(3+x)-1

Is 1-(x+3) the same as (x+3)-1?

1) 2[1-(x+3)]

2) 2(X+3)-1

Is 1-(x+3) the same as (x+3)-1?

1) 2{1-(x+3)}

2) {2(x+3)} -1

Is 1-(x+3) the same as (x-3)-1?

1) (3+x-1)2

2) (3+x)(2)-1

(1-(3+x))x2

(3+x)x2-1

You subtracted the value of 3+x from 1 instead of the other way around. ðŸ˜‰

1.2[1-(3+x)]

How I got my answer was sense I had to double my answer, I multiplied it by two. I put up brackets then subtracted 3+x.

2.[2(3+x)]-1

I put brackets around 2 times 3+x. Then sense I have to subtract 1 from my result I put -1 at the end of my expression.

(3+x)-1=x (5+x)-1=x

3(x)-1â€¢2

3(c)â€¢2-1

I think it’s like that.

1. 1-3+x

2.(3+x)x2-1

1.) 2(1-(x+3)) 2.) 2(x+3)-1

1) ((3+x)-1)*2

2) (3+x)*2-1

—————————————————————————-

1) First, I put parenthesis around 3+x to show that you need to add 3 and x before anything else. Then, I had to subtract 1 from the result of that before doubling anything, so I did ((3+x)-1 to show it. Finally, I put times 2 to double it.

2) First I put parenthesis around 3+x to show that you need to do that before anything else. Then I put *2 to show that you need to double that. I did not put parenthesis around that and 3+x because you still need to follow the order of operations, so I did -1 after *2.

Equation 1: 3+x= x+3-1= x+2*2= x+4

Equation 2: 3+x=x+3*2= x+6

Can you write these expressions without any simplifying?

(3+x-1)to the second power=blank

(3+x)to the second power-1=blank

Is raising something to the second power the same as doubling it?

(3+x-1)*2

(3+X)*2=y-1

There should not be equal signs in expressions.

x+3=

This is not a complete answer Rogelio! You should have two different expressions written down!

3+x-1*2

3+x*2-1

If you put () around an operation, it forces it to go before other operations!

The first expression is (3+x-1)â€¢2.

The second expression is (3+x)â€¢2-1

1.2[(3+x)-1]

2.[(3+x)*2]-1

1-(3+x)2

(3+x)2-1

That is the answerðŸ’©

1.) (3+x)-(1×2)

2.) 2(3+x)-1

(3+x)-1×2

(3+x)x2-1

(3+x)-1×2

(3+x)x2-1 ðŸ™‚

(3+x-1)*2. (3+x)*2=y-1

3+x-1

1-3=-2

i think my answer for the green one is first gonna be [3+x]-1×2

and for my red answer is gonna be [3+x]+3-1

i think my answer for the green one is first gonna be [3+x]-1×2

and for my red answer is gonna be [3+x]+3-1

i think my answer for the green one is first gonna be [3+x]-1×2

and for my red answer is gonna be [3+x]+3-1

2[(3+x)-1]

2(3+x)-1

1) (3+x)-1.2

2) 3+x(2)-1

.=multiplie

[(3+x)-1]*2

[(3+x)2]-1

1) (3+x)-1×2

2) (3+x)x2-1